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4x^2-15x-4=143.489
We move all terms to the left:
4x^2-15x-4-(143.489)=0
We add all the numbers together, and all the variables
4x^2-15x-147.489=0
a = 4; b = -15; c = -147.489;
Δ = b2-4ac
Δ = -152-4·4·(-147.489)
Δ = 2584.824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{2584.824}}{2*4}=\frac{15-\sqrt{2584.824}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{2584.824}}{2*4}=\frac{15+\sqrt{2584.824}}{8} $
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